AssignmeM g 3 Max Marks: 30
Question I: DEFINITION: A positive integer d is culled a divisor of an integer n if and oMy if Ne remainder after n is divided hy d zero. In thi.anew e also say that ” divides n , or Nat , is divisible by,. Here are some examples, • divisor of 35 ; that 35 iq divisible by s. .7 is a na a divisor of 27; that is. 27 is not divisible by 7 .1 is a divisor.’ that is. 14 is divisible by I lin fact. 1 is a divisor.’ every (eager ). 1E is a divisor of 0: that i.0 is divisihle hy 12 C and O. one can test the expresOon n 9f, d to determine whether d is a divisor of n The gra. mime rrfmr of a airy integers m ands Ina bah zero) is the largest positive integer d that is a divisor of both rn and n We sometimes use the abbreviation “gad.’ for “greatest comma diisor. Here are sane etunples: 10 is Jamie g.c.d. 40 and 50; IE is the g.c.d. (01 and 432 ; I is the gc.d.o(256 and 625; 6 is the g.c.d. of 6 and .12 32 is the g.c.d. a0 and 3E. Mite a function named ‘g_
QuatIon positive integer n is said to sepia (or, “a p.m”) if and only if n is greater than 1 and is divisible only by 1 and n. For example, the integers 17 and 29 are prime. but 1 and 38 are not pime. Write a function maned Is_prime.thilt takes apoiiihr :sager argument and returns . its vaue the integer 1 if the argument is p.m and returns the integer° othenvbe. Thus, for exam*. °out isprime1191« endl; // will prim 1 °out « is_prizna I I« end,. A, will prim 0 °out « is_prime1511,« end,. /, will prim 0 °out « endl,/ will print 0
Question 3:
Write a function named .reduoc. that takes two positive integer argumems. call Nein union and .denom”. treats them as tile numerator and denominator of a fraction, and reduces the fracion. That is to say. each of the two arguments will he modified by dividing it by the gremest common sor of the two integos. The Ilmetion should MIMI value.° indicate failure to reduce) if eiNer of the two arguments is zero or negative. and shadd mum the value I oNerwise. Thus, for example, if m and n have hem declared to be kteger voiables in a program, Nen m=25; (red • 15; if uce(mAll cum m « « e.;
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Bruce is a 69 year old retired gentleman. He lives at home with his wife Betty, and together they have three adult children. Bruce is a Vietnam veteran, and as a consequence of his active duty during the war he has developed severe post-traumatic stress disorder and depression. He suffers with hypertension and hypercholesterolemia, but has repeatedly declined any treatment for any of these conditions. Bruce also has a lump on the right underside of his chin that is about the size of a golf ball. Bruce’s wife reports that this lump had been present for many months but despite the fact that it has turned into an open wound with an offensive exudate, Bruce had refuses to seek treatment for it. In recent weeks Bruce has developed symptoms suggestive of an infective illness. He has complained of generalised malaise, muscle aches and pains and an elevated temperature with occasional rigors. Despite the best efforts of Betty and the children, Bruce has refused to seek medical attention for these symptoms even as his condition deteriorated. Eventually Bruce became so weak and dehydrated that he was no longer able to refuse Betty’s efforts to have him see a doctor; with the assistance of their children Betty manoeuvred him into the car and took him to hospital. On admission to the hospital Bruce was noted to be hypotensive, tachycardic and febrile. His level of consciousness fluctuated, and was often only minimally responsive. Concerned that he may not be able to adequately protect his airway, Bruce was transferred to the high dependency unit where he could be closely monitored. Bruce was diagnosed with septicaemia resulting from the open wound under his chin
March 26, 2015
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