Consider applying the simple electronic polarizability and Clasius-Mossotti equations to diamond.
Neglecting losses,
α
ω ω e
e o
Ze
m
=
−
2
( 2 2 )
and ε
ε ε ω ω
r
r o e o
NZe
m
−
+
=
−
1
2 3
2
( 2 2 )
Dispersion in diamond
For diamond we can take Z = 4 (valence electrons only as these are the most responsive),
N = 1.8 × 1029 atoms m-3, εr(DC) = 5.7. Find ωo and then find the refractive index at λ = 0.5 μm and
5 μm.